Given all else being equal and taking into account no other variable, will increasing the length/depth of the lugs or cleats on a tracked vehicle such as a snowmobile cause a definable change in the vehicles final drive ratio. For the purpose of this question final drive ratio is to be defined as the distance the vehicle moves with one full rotation of the drive system input and not accounting for any variation in the drivetrain such as CVT etc. 

 

I am open to suggestions but I think the above about covers it.

1 minute ago, Polaris 550 said:

I should know, but I'm bad at math and @f7ben is gonna take me for $20gs...............$2.00 BLOW-JOB SPECIALS!!

COME GET EM!!

Are you a site sponsor?

2 minutes ago, awful knawful said:

😁😂😂

Don't you just hate the " OWNAGE " I've handed ya' Dragqueen? 

It eats away at ya', doesn't it ??? 

Yeah, it does. 

I took the bet mach....I accept your challenge. Let's pic an engineering firm to settle it.

The wager has been made , 20k

Time to man up @Polaris 550!

Time to shut the cock warmer and settle this!

I accept the bet....I have articulated the question. The wager is 20k

I accept the challenge!!!11

16 hours ago, f7ben said:

So dumb its almost like he's trolling

121” Cut a track lay it out flat.  Drop and roll the chain case so that the driver hits the track that is laid flat...  turn the secondary 1 rotation and the sled will move an easily computed distance.

cut a 151 track and lay it flat.  Pick the sled off the 121 track and set it on the 151.  Turn the secondary one revolution and the sled move the same distance as it did on the 121....

Edited December 17, 20186 yr by BOHICA

Just now, BOHICA said:

121” Cut a track lay it out flat.  Drop and roll the chain case so that the driver hits the track that is laid flat...  turn the secondary 1 rotation and the sled will move a easily computed distance.

cut a 151 track and lay it flat.  Pick the sled off the 121 track and set it on the 151.  Turn the secondary one revolution and the sled move the same distance as it did on the 121....

Of course

1 minute ago, f7ben said:

I accept the bet....I have articulated the question. The wager is 20k

I accept the challenge!!!11

Ben has manned up!

Nobody else???

Just now, f7ben said:

Of course

Yep.  Neal is the only one here who doesn't get it.   

2 minutes ago, awful knawful said:

Ben has manned up!

Nobody else???

I accepted the bet for a lesser sum.  

1 minute ago, AKIQPilot said:

I accepted the bet for a lesser sum.  

I have accepted a 5k bet from him and now 20k

I will transfer the money to an EJ account and woolie can verify funds. If I lose I will transfer those funds right to znutty.

I will transfer 20k verified funds to an EJ account .....

19 minutes ago, Polaris 550 said:

NO!!! 

Wager wisely.  Down 415 now.  

this has been a riot.

With the wording of the question, the only way lug height would result in a different distance traveled would be if the sled were riding a massive wheelie and riding on the rear axle.  Then the whole "bigger tire diameter" argument would come into play.

Edited December 17, 20186 yr by Matt

1 hour ago, Polaris 550 said:

All other factors being constant, does lug height affect the FINAL DRIVE RATIO on a snowmobile, on a hypothetical, flat hard plane??? 

In other words, will a snowmobile travel further with one rotation of the track with 3" lugs, as compared to that same snowmobile with 1" lugs.  

I would say that the size of the cog wheels on the driven axel that are turning the track would be what would change the speed in this disaster of an argument. 

A conveyor belt will go the same speed weather it's longer, shorter, thicker, thinner..... it's the change in the size of the wheel that's spinning the dam thing that would affect the speed of the belt in this example.  Put this drive wheel in the middle of the conveyor belt where it's flat.  Is a thicker / thinner belt going to spin any different if the wheel turning it stays constant?

2 hours ago, Matt said:

This was not the question in the OP.  He didn't ask about one full rotation of the track.  He asked about one full rotation of the input.

@motonoggin is correct.  Lug height is not what's important.  The track is being laid down and the bogies are rolling across it and slides are sliding across it.  Regardless of lug height, if the track driver pitch is exactly the same on a 1" lug or a 3" lug, the suspension will only roll one driver rotation-worth of track LENGTH.  Assuming no lug flex is present.

Put another way, if the circumference of the driver is 20 inches and there's a 4:1 reduction in the chaincase, one rotation of the jackshaft will result in 5 inches worth of track being laid down, regardless of the lug height.

Znotty after this is all over...........................

 

Ill bet anyone $50 that these 2 dudes will never get this bet going

Just now, steve from amherst said:

Ill bet anyone $50 that these 2 dudes will never get this bet going

I'm trying ....znutty knows he lost

4 hours ago, AKIQPilot said:

Absolutely wrong.  Not once did you quantify your position.  You did not prove that a track with 3" lugs would move a vehicle more or less than a track with 1" lugs with one or more rotation of the track.  You provided a theory but never quantified your theory with an answer.  

If you think I'm wrong about that then provide the answer again.  How much more or less will a 3" lug move a vehicle over a 1" lug with 1 or 100 or 1000 rotations of the track.  

They will, for all practical measurements move the same. 

Your inability to not comprehend isn't my fault.  I have provided my position and with supporting argument.  I apologise if my inability to explain the position is unable to convince you.  That however doesn't change my position, nor the validity it has.

As I see it you can either try to engage in a meaningful discourse about it, or keep with the constant disregarding out of hand, wether out of spite, personal dislike, or unwillingness to understand.  I certainly prefer conversations of the former, especially for members I have met and hold great respect for.

Neal

3 hours ago, motonoggin said:

No, it won't be correct, but that's because it's rotational motion, not linear.

 

Where is the type of motion defined in the final drive ratio?

Neal

2 minutes ago, NaturallyAspirated said:

They will, for all practical measurements move the same. 

Your inability to not comprehend isn't my fault.  I have provided my position and with supporting argument.  I apologise if my inability to explain the position is unable to convince you.  That however doesn't change my position, nor the validity it has.

As I see it you can either try to engage in a meaningful discourse about it, or keep with the constant disregarding out of hand, wether out of spite, personal dislike, or unwillingness to understand.  I certainly prefer conversations of the former, especially for members I have met and hold great respect for.

Neal

I HAVE ZERO RESPECT FOR YOU LANEALSHA!!!!!1++ ahahahaba

Just now, NaturallyAspirated said:

Where is the type of motion defined in the final drive ratio?

Neal

It is inherent to a tracked  vehicle 

4 minutes ago, f7ben said:

I HAVE ZERO RESPECT FOR YOU LANEALSHA!!!!!1++ ahahahaba

I respect your brother more than you Bhent!

🤗 

Neal

29 minutes ago, steve from amherst said:

Ill bet anyone $50 that these 2 dudes will never get this bet going

I was going to post the same exact thing!